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ÃbHÏ
23 Oct 18

Let x be the A.M. y , z be the two G.Ms between two positive numbers. Then [y^3 + z^3] / xyz =?

Replies to this post

A
Adithya

x=A+B/2 y=√Az z=√By y^3+z^3/xyz=y^3/xyz + z^3/xyz =y^2/xz + z^2/xy = Az/xz + By/xy =A+B/x = 2

2
Ã
ÃbHÏ

Ohkk...,thnx dude.

2
Y
Yazeed

Let (a,b) be the to numbers And AM=X==a+b/2 The two GM=Y=a^2/3 ×b^1/3 And. Z=a^1/3 ×b^2/3 Hence

Y^3+z^3=ab(a+b) XYZ=ab (a+b)/2 Hence required answer=2

1