S
Sudeeptvd
06 Jun 18

please answer q no 5

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R
Remya

Number of integers divisible by 2 between 1 and 100 can calculated as 100= 2+(n-1)*2 N=50 Sum of integers = n/2(2a+(n-1)d) = 50/2(4+98) = 2550 Similarly numbers divisible by 5 100= 5+(n-1)5 N=20 Sum = 20/2(10+95) =1050 The numbers divisible by both 2 and 5= 100=10+(n-1)10 n=10 It's sum= 10/2(20+90) There for the final required sum =2550+1050-550=3050

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