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Fathimath
24 Apr 19

Pls give the ans fast....opt a can be correct since elongation under its own weight

Replies to this post

T
Theresa

Weight of rod=mg Area=A Stress= mg/A Let change of length= l' Original length=l Strain= l'/l Youngs modulus Y= (mg/A)/(l'/l) Y= mgl/Al' l'=mgl/AY

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Shailja

Yes answer should be 1st....bcs under own weight we use avg of top and bottom points.....

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F
Fathimath

When such a question comes in which way do we have to approach

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