Let x be the A.M. y , z be the two G.Ms between two positive numbers. Then [y^3 + z^3] / xyz =?
x=A+B/2 y=√Az z=√By y^3+z^3/xyz=y^3/xyz + z^3/xyz =y^2/xz + z^2/xy = Az/xz + By/xy =A+B/x = 2
Ohkk...,thnx dude.
Let (a,b) be the to numbers And AM=X==a+b/2 The two GM=Y=a^2/3 ×b^1/3 And. Z=a^1/3 ×b^2/3 Hence
Y^3+z^3=ab(a+b) XYZ=ab (a+b)/2 Hence required answer=2