F
Fathimath
10 Apr 19

Question 57 somebody pls answer

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T
Theresa

Quantity of charge passed= 0.53060= 900 coulomb 900 coulomb deposite copper = 0.2964g 96500 coulomb deposite = (0.2964*96500)/900 = 31.78g Hence with atomic mass 63.56 The oxidation number is +2

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